-16x^2+100x+5=100

Solution for -16x^2+100x+5=100 equation:

-16x^2+100x+5=100

We move all terms to the left:

-16x^2+100x+5-(100)=0

We add all the numbers together, and all the variables

-16x^2+100x-95=0

a = -16; b = 100; c = -95;
Δ = b2-4ac
Δ = 1002-4·(-16)·(-95)
Δ = 3920
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3920}=\sqrt{784*5}=\sqrt{784}*\sqrt{5}=28\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-28\sqrt{5}}{2*-16}=\frac{-100-28\sqrt{5}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+28\sqrt{5}}{2*-16}=\frac{-100+28\sqrt{5}}{-32}
$